WebApr 2, 2012 · These three numbers as 1251,9377 and 15628 will be divisible by the largest number if we deduct the remain ders from them respectively. So, 1251-1=1250, 9337-2=9335, and 15628-3=15625. Now we find out HCF of these numbers which will be its required answer. Hcf(1250,9375,15625)=625 ( By Division method to find HCF) WebHCF of 1250, 9375 and 15625 is 625. Hence, the largest number that divides 1251, 9377 and 15628 leaving remainders 1, 2 and 3 respectively is 625. Real Numbers Exercise …
Find the largest no that divides 1251, 9377, 15628 leaving ... - Brainly
WebApr 24, 2024 · Find an answer to your question hcf of 1250 9375 15625 ... Advertisement shirikavi shirikavi here is your answer mate. hcf =625. OK no it's incorrect Advertisement … WebWe have the numbers, 1251 - 1 = 1250, 9377 - 2 = 9375 and 15628 - 3 = 15625 which is divisible by the required number. Now, required number = HCF of 1250, 9375 and 15625 [for the largest number] By Euclid's division algorithm, a = bq + r [∵ D i v i d e n d = D i v i s o r × Q u o t i e n t + R e m a i n d e r] For largest number, put a ... how to activate lvm
HCF of 1250, 9375, 15625 using Euclid
WebOn subtracting 1, 2, and 3 from 1251, 9377 and 15628 respectively, we get 1250, 9375 and 15625. Now we find the HCF of 1250 and 9375 using Euclid's division lemma 1250 < 9375 Thus, we divide 9375 by 1250 by using Euclid's division lemma 9375 = 1250 × 7 + 625 ∵ Remainder is not zero, ∴ we divide 1250 by 625 by using Euclid's division lemma WebAug 23, 2024 · 1251 – 1 = 1250, 9377 − 2 = 9375 and 15628 − 3 = 15625 which is divisible by the required number. Now, required number = HCF (1250, 9375, 15625) By Euclid’s division algorithm, b = a × q + r, 0 ≤ r < a. Here, b is any positive integer . Firstly put b = 15625 and a = 9375. WebThe greatest common factor (GCF or GCD or HCF) of a set of whole numbers is the largest positive integer that divides evenly into all numbers with zero remainder. For example, for the set of numbers 18, 30 and 42 … how to activate lvb debit card